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8n^2+49n-49=0
a = 8; b = 49; c = -49;
Δ = b2-4ac
Δ = 492-4·8·(-49)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-63}{2*8}=\frac{-112}{16} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+63}{2*8}=\frac{14}{16} =7/8 $
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